Search a number
-
+
112120312110300 = 2232521341922870961
BaseRepresentation
bin11001011111100100001011…
…011000000001110011011100
3112200222121010022212002102100
4121133210023120001303130
5104143434344400012200
61034243205454525100
732421265566215604
oct3137441330016334
9480877108762370
10112120312110300
11327a7a5924119a
12106a9801806790
134a73b9159ac30
141d9891b37dc04
15ce678ec97d00
hex65f90b601cdc

112120312110300 has 216 divisors, whose sum is σ = 379371624755760. Its totient is φ = 27532976486400.

The previous prime is 112120312110283. The next prime is 112120312110319. The reversal of 112120312110300 is 3011213021211.

112120312110300 is a `hidden beast` number, since 1 + 1 + 2 + 120 + 31 + 211 + 0 + 300 = 666.

It is a super-2 number, since 2×1121203121103002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 6533181 + ... + 16337780.

It is an arithmetic number, because the mean of its divisors is an integer number (1756350114610).

Almost surely, 2112120312110300 is an apocalyptic number.

112120312110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

112120312110300 is an abundant number, since it is smaller than the sum of its proper divisors (267251312645460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112120312110300 is a wasteful number, since it uses less digits than its factorization.

112120312110300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22871413 (or 22871403 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 112120312110300 its reverse (3011213021211), we get a palindrome (115131525131511).

It can be divided in two parts, 11212031 and 2110300, that added together give a palindrome (13322331).

The spelling of 112120312110300 in words is "one hundred twelve trillion, one hundred twenty billion, three hundred twelve million, one hundred ten thousand, three hundred".