Base | Representation |
---|---|
bin | 11001011111100100111010… |
… | …111100100100110110010011 |
3 | 112200222200011221122021100111 |
4 | 121133210322330210312103 |
5 | 104143443013204021204 |
6 | 1034243421005102151 |
7 | 32421324430100554 |
oct | 3137447274446623 |
9 | 480880157567314 |
10 | 112121110220179 |
11 | 327a8328800a35 |
12 | 106a99a4b57957 |
13 | 4a73c8aa3b6b8 |
14 | 1d9899537632b |
15 | ce67d9d99d04 |
hex | 65f93af24d93 |
112121110220179 has 2 divisors, whose sum is σ = 112121110220180. Its totient is φ = 112121110220178.
The previous prime is 112121110220173. The next prime is 112121110220183. The reversal of 112121110220179 is 971022011121211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112121110220179 - 27 = 112121110220051 is a prime.
It is a super-2 number, since 2×1121211102201792 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 112121110220179.
It is not a weakly prime, because it can be changed into another prime (112121110220173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060555110089 + 56060555110090.
It is an arithmetic number, because the mean of its divisors is an integer number (56060555110090).
Almost surely, 2112121110220179 is an apocalyptic number.
112121110220179 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121110220179 is an equidigital number, since it uses as much as digits as its factorization.
112121110220179 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 31.
The spelling of 112121110220179 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred ten million, two hundred twenty thousand, one hundred seventy-nine".
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