Base | Representation |
---|---|
bin | 11001011111100100111011… |
… | …100010101100010001001011 |
3 | 112200222200012122102220121112 |
4 | 121133210323202230101023 |
5 | 104143443023233241133 |
6 | 1034243422003200535 |
7 | 32421324611034425 |
oct | 3137447342542113 |
9 | 480880178386545 |
10 | 112121120212043 |
11 | 327a8333405a78 |
12 | 106a99a837614b |
13 | 4a73c8cb29647 |
14 | 1d98996817815 |
15 | ce67dabc0648 |
hex | 65f93b8ac44b |
112121120212043 has 2 divisors, whose sum is σ = 112121120212044. Its totient is φ = 112121120212042.
The previous prime is 112121120211901. The next prime is 112121120212069. The reversal of 112121120212043 is 340212021121211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112121120212043 - 28 = 112121120211787 is a prime.
It is a super-2 number, since 2×1121211202120432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112121120212093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060560106021 + 56060560106022.
It is an arithmetic number, because the mean of its divisors is an integer number (56060560106022).
Almost surely, 2112121120212043 is an apocalyptic number.
112121120212043 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121120212043 is an equidigital number, since it uses as much as digits as its factorization.
112121120212043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 112121120212043 its reverse (340212021121211), we get a palindrome (452333141333254).
The spelling of 112121120212043 in words is "one hundred twelve trillion, one hundred twenty-one billion, one hundred twenty million, two hundred twelve thousand, forty-three".
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