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112121231313001 is a prime number
BaseRepresentation
bin11001011111100101000010…
…001010100000100001101001
3112200222200111101111102110211
4121133211002022200201221
5104143443240204004001
61034243441012341121
732421330430263061
oct3137450212404151
9480880441442424
10112121231313001
11327a8390099849
12106a9a196147a1
134a73ca9b58b61
141d989a74983a1
15ce67e5819351
hex65f9422a0869

112121231313001 has 2 divisors, whose sum is σ = 112121231313002. Its totient is φ = 112121231313000.

The previous prime is 112121231312983. The next prime is 112121231313011. The reversal of 112121231313001 is 100313132121211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74402717741401 + 37718513571600 = 8625701^2 + 6141540^2 .

It is a cyclic number.

It is not a de Polignac number, because 112121231313001 - 235 = 112086871574633 is a prime.

It is a super-2 number, since 2×1121212313130012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112121231313011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060615656500 + 56060615656501.

It is an arithmetic number, because the mean of its divisors is an integer number (56060615656501).

Almost surely, 2112121231313001 is an apocalyptic number.

It is an amenable number.

112121231313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121231313001 is an equidigital number, since it uses as much as digits as its factorization.

112121231313001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 112121231313001 its reverse (100313132121211), we get a palindrome (212434363434212).

The spelling of 112121231313001 in words is "one hundred twelve trillion, one hundred twenty-one billion, two hundred thirty-one million, three hundred thirteen thousand, one".