Search a number
-
+
112122020033 is a prime number
BaseRepresentation
bin110100001101011111…
…1100100000011000001
3101201101222100202121122
41220122333210003001
53314111214120113
6123301432002025
711046326305532
oct1503277440301
9351358322548
10112122020033
1143606a59181
1219891530315
13a75b02776a
1455d8d62689
152db355e408
hex1a1afe40c1

112122020033 has 2 divisors, whose sum is σ = 112122020034. Its totient is φ = 112122020032.

The previous prime is 112122020009. The next prime is 112122020047. The reversal of 112122020033 is 330020221211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56957163649 + 55164856384 = 238657^2 + 234872^2 .

It is an emirp because it is prime and its reverse (330020221211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112122020033 - 26 = 112122019969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112122019993 and 112122020020.

It is not a weakly prime, because it can be changed into another prime (112122026033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061010016 + 56061010017.

It is an arithmetic number, because the mean of its divisors is an integer number (56061010017).

Almost surely, 2112122020033 is an apocalyptic number.

It is an amenable number.

112122020033 is a deficient number, since it is larger than the sum of its proper divisors (1).

112122020033 is an equidigital number, since it uses as much as digits as its factorization.

112122020033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 112122020033 its reverse (330020221211), we get a palindrome (442142241244).

The spelling of 112122020033 in words is "one hundred twelve billion, one hundred twenty-two million, twenty thousand, thirty-three".