Base | Representation |
---|---|
bin | 10000010100001101111… |
… | …110101011110001011011 |
3 | 10222012001211010021111012 |
4 | 100110031332223301123 |
5 | 121332230034002113 |
6 | 2215025401124135 |
7 | 144001621153016 |
oct | 20241576536133 |
9 | 3865054107435 |
10 | 1121221000283 |
11 | 3a256402a65a |
12 | 16137278964b |
13 | 8196641ab87 |
14 | 3c3a59c837d |
15 | 1e273a04aa8 |
hex | 1050dfabc5b |
1121221000283 has 2 divisors, whose sum is σ = 1121221000284. Its totient is φ = 1121221000282.
The previous prime is 1121221000171. The next prime is 1121221000297. The reversal of 1121221000283 is 3820001221211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121221000283 - 224 = 1121204223067 is a prime.
It is a super-2 number, since 2×11212210002832 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1121221050283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560610500141 + 560610500142.
It is an arithmetic number, because the mean of its divisors is an integer number (560610500142).
Almost surely, 21121221000283 is an apocalyptic number.
1121221000283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121221000283 is an equidigital number, since it uses as much as digits as its factorization.
1121221000283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1121221000283 its reverse (3820001221211), we get a palindrome (4941222221494).
The spelling of 1121221000283 in words is "one trillion, one hundred twenty-one billion, two hundred twenty-one million, two hundred eighty-three", and thus it is an aban number.
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