Base | Representation |
---|---|
bin | 11001011111100101110101… |
… | …111100101101111100111011 |
3 | 112200222202201221022001022101 |
4 | 121133211311330231330323 |
5 | 104144002030112110321 |
6 | 1034244103130004231 |
7 | 32421361110045226 |
oct | 3137456574557473 |
9 | 480882657261271 |
10 | 112122100113211 |
11 | 327a8796551251 |
12 | 106aa020576677 |
13 | 4a740b7b4a416 |
14 | 1d98a4aa125bd |
15 | ce6846c31791 |
hex | 65f975f2df3b |
112122100113211 has 2 divisors, whose sum is σ = 112122100113212. Its totient is φ = 112122100113210.
The previous prime is 112122100113203. The next prime is 112122100113263. The reversal of 112122100113211 is 112311001221211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112122100113211 - 23 = 112122100113203 is a prime.
It is not a weakly prime, because it can be changed into another prime (112122100117211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061050056605 + 56061050056606.
It is an arithmetic number, because the mean of its divisors is an integer number (56061050056606).
Almost surely, 2112122100113211 is an apocalyptic number.
112122100113211 is a deficient number, since it is larger than the sum of its proper divisors (1).
112122100113211 is an equidigital number, since it uses as much as digits as its factorization.
112122100113211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 112122100113211 its reverse (112311001221211), we get a palindrome (224433101334422).
The spelling of 112122100113211 in words is "one hundred twelve trillion, one hundred twenty-two billion, one hundred million, one hundred thirteen thousand, two hundred eleven".
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