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11212210033 is a prime number
BaseRepresentation
bin10100111000100110…
…01011111101110001
31001221101202021200021
422130103023331301
5140430311210113
65052324323441
7544564132663
oct123423137561
931841667607
1011212210033
114834000392
12220ab43581
131098b9840b
14785150533
1545950b48d
hex29c4cbf71

11212210033 has 2 divisors, whose sum is σ = 11212210034. Its totient is φ = 11212210032.

The previous prime is 11212210007. The next prime is 11212210043. The reversal of 11212210033 is 33001221211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7979491584 + 3232718449 = 89328^2 + 56857^2 .

It is a cyclic number.

It is not a de Polignac number, because 11212210033 - 25 = 11212210001 is a prime.

It is a super-2 number, since 2×112122100332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11212209989 and 11212210016.

It is not a weakly prime, because it can be changed into another prime (11212210003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606105016 + 5606105017.

It is an arithmetic number, because the mean of its divisors is an integer number (5606105017).

Almost surely, 211212210033 is an apocalyptic number.

It is an amenable number.

11212210033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212210033 is an equidigital number, since it uses as much as digits as its factorization.

11212210033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11212210033 its reverse (33001221211), we get a palindrome (44213431244).

The spelling of 11212210033 in words is "eleven billion, two hundred twelve million, two hundred ten thousand, thirty-three".