Base | Representation |
---|---|
bin | 11001011111100111101111… |
… | …000101110011111011010011 |
3 | 112200222221222120200000212220 |
4 | 121133213233011303323103 |
5 | 104144020210412240430 |
6 | 1034245040531552123 |
7 | 32421462346304133 |
oct | 3137475705637323 |
9 | 480887876600786 |
10 | 112124132540115 |
11 | 327a9639826703 |
12 | 106aa4a915b643 |
13 | 4a7434cc392a7 |
14 | 1d98ba090cac3 |
15 | ce691539c110 |
hex | 65f9ef173ed3 |
112124132540115 has 32 divisors (see below), whose sum is σ = 185585660006400. Its totient is φ = 57737207794560.
The previous prime is 112124132540071. The next prime is 112124132540143. The reversal of 112124132540115 is 511045231421211.
It is a happy number.
It is not a de Polignac number, because 112124132540115 - 226 = 112124065431251 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 115294950 + ... + 116263380.
It is an arithmetic number, because the mean of its divisors is an integer number (5799551875200).
Almost surely, 2112124132540115 is an apocalyptic number.
112124132540115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112124132540115 is a deficient number, since it is larger than the sum of its proper divisors (73461527466285).
112124132540115 is a wasteful number, since it uses less digits than its factorization.
112124132540115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1234627.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 112124132540115 its reverse (511045231421211), we get a palindrome (623169363961326).
The spelling of 112124132540115 in words is "one hundred twelve trillion, one hundred twenty-four billion, one hundred thirty-two million, five hundred forty thousand, one hundred fifteen".
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