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11212433 is a prime number
BaseRepresentation
bin101010110001…
…011010010001
3210002122120022
4222301122101
510332244213
61040153225
7164206211
oct52613221
923078508
1011212433
116369081
123908815
13242769b
1416bc241
15eb7308
hexab1691

11212433 has 2 divisors, whose sum is σ = 11212434. Its totient is φ = 11212432.

The previous prime is 11212429. The next prime is 11212447. The reversal of 11212433 is 33421211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7997584 + 3214849 = 2828^2 + 1793^2 .

It is a cyclic number.

It is not a de Polignac number, because 11212433 - 22 = 11212429 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11212633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606216 + 5606217.

It is an arithmetic number, because the mean of its divisors is an integer number (5606217).

Almost surely, 211212433 is an apocalyptic number.

It is an amenable number.

11212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212433 is an equidigital number, since it uses as much as digits as its factorization.

11212433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 17.

The square root of 11212433 is about 3348.4971255774. The cubic root of 11212433 is about 223.8205474411.

Adding to 11212433 its reverse (33421211), we get a palindrome (44633644).

The spelling of 11212433 in words is "eleven million, two hundred twelve thousand, four hundred thirty-three".