Base | Representation |
---|---|
bin | 110100001101101001… |
… | …1111001110010010001 |
3 | 101201102100101122122011 |
4 | 1220123103321302101 |
5 | 3314114100230303 |
6 | 123302142142521 |
7 | 11046422523511 |
oct | 1503323716221 |
9 | 351370348564 |
10 | 112127351953 |
11 | 43609a70121 |
12 | 19893281a41 |
13 | a75c173646 |
14 | 55d994d841 |
15 | 2db3c6416d |
hex | 1a1b4f9c91 |
112127351953 has 2 divisors, whose sum is σ = 112127351954. Its totient is φ = 112127351952.
The previous prime is 112127351879. The next prime is 112127351981. The reversal of 112127351953 is 359153721211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104954617089 + 7172734864 = 323967^2 + 84692^2 .
It is a cyclic number.
It is not a de Polignac number, because 112127351953 - 225 = 112093797521 is a prime.
It is not a weakly prime, because it can be changed into another prime (112127301953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56063675976 + 56063675977.
It is an arithmetic number, because the mean of its divisors is an integer number (56063675977).
Almost surely, 2112127351953 is an apocalyptic number.
It is an amenable number.
112127351953 is a deficient number, since it is larger than the sum of its proper divisors (1).
112127351953 is an equidigital number, since it uses as much as digits as its factorization.
112127351953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 56700, while the sum is 40.
The spelling of 112127351953 in words is "one hundred twelve billion, one hundred twenty-seven million, three hundred fifty-one thousand, nine hundred fifty-three".
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