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11213001003101 = 21115311701091
BaseRepresentation
bin1010001100101011101011…
…1100010001000001011101
31110200221201022121202021012
42203022322330101001131
52432203211224044401
635503103114145005
72235053421633422
oct243127274210135
943627638552235
1011213001003101
113633452820177
1213111a3422165
136344c60a6671
142aa9d81a3d49
15146a211cc8bb
hexa32baf1105d

11213001003101 has 4 divisors (see below), whose sum is σ = 11218312706304. Its totient is φ = 11207689299900.

The previous prime is 11213001003097. The next prime is 11213001003119. The reversal of 11213001003101 is 10130010031211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11213001003101 - 22 = 11213001003097 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213001003301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2655848435 + ... + 2655852656.

It is an arithmetic number, because the mean of its divisors is an integer number (2804578176576).

Almost surely, 211213001003101 is an apocalyptic number.

It is an amenable number.

11213001003101 is a deficient number, since it is larger than the sum of its proper divisors (5311703203).

11213001003101 is an equidigital number, since it uses as much as digits as its factorization.

11213001003101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5311703202.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11213001003101 its reverse (10130010031211), we get a palindrome (21343011034312).

The spelling of 11213001003101 in words is "eleven trillion, two hundred thirteen billion, one million, three thousand, one hundred one".

Divisors: 1 2111 5311701091 11213001003101