Base | Representation |
---|---|
bin | 110100001101110000… |
… | …1101100100111111001 |
3 | 101201102121012100222221 |
4 | 1220123201230213321 |
5 | 3314121011434212 |
6 | 123302351444041 |
7 | 11046465334213 |
oct | 1503341544771 |
9 | 351377170887 |
10 | 112130968057 |
11 | 4361100aa39 |
12 | 19894526621 |
13 | a75cb3b554 |
14 | 55da2115b3 |
15 | 2db422a807 |
hex | 1a1b86c9f9 |
112130968057 has 2 divisors, whose sum is σ = 112130968058. Its totient is φ = 112130968056.
The previous prime is 112130967983. The next prime is 112130968069. The reversal of 112130968057 is 750869031211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72725144976 + 39405823081 = 269676^2 + 198509^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112130968057 is a prime.
It is not a weakly prime, because it can be changed into another prime (112170968057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065484028 + 56065484029.
It is an arithmetic number, because the mean of its divisors is an integer number (56065484029).
Almost surely, 2112130968057 is an apocalyptic number.
It is an amenable number.
112130968057 is a deficient number, since it is larger than the sum of its proper divisors (1).
112130968057 is an equidigital number, since it uses as much as digits as its factorization.
112130968057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 43.
Adding to 112130968057 its reverse (750869031211), we get a palindrome (862999999268).
The spelling of 112130968057 in words is "one hundred twelve billion, one hundred thirty million, nine hundred sixty-eight thousand, fifty-seven".
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