Search a number
-
+
112131031403 is a prime number
BaseRepresentation
bin110100001101110000…
…1111100000101101011
3101201102121022120220002
41220123201330011223
53314121021001103
6123302353053215
711046466016666
oct1503341740553
9351377276802
10112131031403
1143611053596
121989455720b
13a75cb61331
1455da22a6dd
152db423e488
hex1a1b87c16b

112131031403 has 2 divisors, whose sum is σ = 112131031404. Its totient is φ = 112131031402.

The previous prime is 112131031343. The next prime is 112131031417. The reversal of 112131031403 is 304130131211.

It is a strong prime.

It is an emirp because it is prime and its reverse (304130131211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112131031403 - 216 = 112130965867 is a prime.

It is not a weakly prime, because it can be changed into another prime (112131031703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065515701 + 56065515702.

It is an arithmetic number, because the mean of its divisors is an integer number (56065515702).

Almost surely, 2112131031403 is an apocalyptic number.

112131031403 is a deficient number, since it is larger than the sum of its proper divisors (1).

112131031403 is an equidigital number, since it uses as much as digits as its factorization.

112131031403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 112131031403 its reverse (304130131211), we get a palindrome (416261162614).

The spelling of 112131031403 in words is "one hundred twelve billion, one hundred thirty-one million, thirty-one thousand, four hundred three".