Base | Representation |
---|---|
bin | 10000010100010011010… |
… | …110011011100010100011 |
3 | 10222012022002200101121102 |
4 | 100110103112123202203 |
5 | 121332421121030311 |
6 | 2215042340345015 |
7 | 144004064120315 |
oct | 20242326334243 |
9 | 3865262611542 |
10 | 1121311111331 |
11 | 3a25aa9873a4 |
12 | 1613989a516b |
13 | 8197bcab518 |
14 | 3c3b39637b5 |
15 | 1e27b8a443b |
hex | 1051359b8a3 |
1121311111331 has 2 divisors, whose sum is σ = 1121311111332. Its totient is φ = 1121311111330.
The previous prime is 1121311111303. The next prime is 1121311111411. The reversal of 1121311111331 is 1331111131211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121311111331 - 26 = 1121311111267 is a prime.
It is a super-2 number, since 2×11213111113312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1121311114331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560655555665 + 560655555666.
It is an arithmetic number, because the mean of its divisors is an integer number (560655555666).
Almost surely, 21121311111331 is an apocalyptic number.
1121311111331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121311111331 is an equidigital number, since it uses as much as digits as its factorization.
1121311111331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54, while the sum is 20.
Adding to 1121311111331 its reverse (1331111131211), we get a palindrome (2452422242542).
The spelling of 1121311111331 in words is "one trillion, one hundred twenty-one billion, three hundred eleven million, one hundred eleven thousand, three hundred thirty-one".
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