Base | Representation |
---|---|
bin | 10100111000101101… |
… | …01100100100011110 |
3 | 1001221110111000122122 |
4 | 22130112230210132 |
5 | 140431030130024 |
6 | 5052400142542 |
7 | 544605014102 |
oct | 123426544436 |
9 | 31843430578 |
10 | 11213130014 |
11 | 48345795a9 |
12 | 220b307a52 |
13 | 109912b098 |
14 | 78530d902 |
15 | 45963dd5e |
hex | 29c5ac91e |
11213130014 has 4 divisors (see below), whose sum is σ = 16819695024. Its totient is φ = 5606565006.
The previous prime is 11213129981. The next prime is 11213130031. The reversal of 11213130014 is 41003131211.
11213130014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11213129974 and 11213130001.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803282502 + ... + 2803282505.
It is an arithmetic number, because the mean of its divisors is an integer number (4204923756).
Almost surely, 211213130014 is an apocalyptic number.
11213130014 is a deficient number, since it is larger than the sum of its proper divisors (5606565010).
11213130014 is an equidigital number, since it uses as much as digits as its factorization.
11213130014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5606565009.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11213130014 its reverse (41003131211), we get a palindrome (52216261225).
The spelling of 11213130014 in words is "eleven billion, two hundred thirteen million, one hundred thirty thousand, fourteen".
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