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11213133302153 is a prime number
BaseRepresentation
bin1010001100101100001011…
…0100111100100110001001
31110200222001112120020110002
42203023002310330212021
52432203444111132103
635503124201532345
72235056616311066
oct243130264744611
943628045506402
1011213133302153
113633510472432
12131121b7a40b5
13634517618723
142aaa0b9a1c6d
15146a2cb12488
hexa32c2d3c989

11213133302153 has 2 divisors, whose sum is σ = 11213133302154. Its totient is φ = 11213133302152.

The previous prime is 11213133302051. The next prime is 11213133302167. The reversal of 11213133302153 is 35120333131211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10757632493689 + 455500808464 = 3279883^2 + 674908^2 .

It is a cyclic number.

It is not a de Polignac number, because 11213133302153 - 212 = 11213133298057 is a prime.

It is not a weakly prime, because it can be changed into another prime (11213133332153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606566651076 + 5606566651077.

It is an arithmetic number, because the mean of its divisors is an integer number (5606566651077).

Almost surely, 211213133302153 is an apocalyptic number.

It is an amenable number.

11213133302153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213133302153 is an equidigital number, since it uses as much as digits as its factorization.

11213133302153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 11213133302153 its reverse (35120333131211), we get a palindrome (46333466433364).

The spelling of 11213133302153 in words is "eleven trillion, two hundred thirteen billion, one hundred thirty-three million, three hundred two thousand, one hundred fifty-three".