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1121314101441 = 33727100287461
BaseRepresentation
bin10000010100010011100…
…001110101100011000001
310222012022022022022021020
4100110103201311203001
5121332422402221231
62215042524420053
7144004131412662
oct20242341654301
93865268268236
101121314101441
113a2601639966
121613999a7629
138197c7b7511
143c3b4101369
151e27bc95396
hex105138758c1

1121314101441 has 8 divisors (see below), whose sum is σ = 1495486633344. Its totient is φ = 747342151920.

The previous prime is 1121314101419. The next prime is 1121314101443. The reversal of 1121314101441 is 1441014131211.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1121314101441 - 215 = 1121314068673 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1121314101443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50132550 + ... + 50154911.

It is an arithmetic number, because the mean of its divisors is an integer number (186935829168).

Almost surely, 21121314101441 is an apocalyptic number.

It is an amenable number.

1121314101441 is a deficient number, since it is larger than the sum of its proper divisors (374172531903).

1121314101441 is a wasteful number, since it uses less digits than its factorization.

1121314101441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100291191.

The product of its (nonzero) digits is 384, while the sum is 24.

Adding to 1121314101441 its reverse (1441014131211), we get a palindrome (2562328232652).

The spelling of 1121314101441 in words is "one trillion, one hundred twenty-one billion, three hundred fourteen million, one hundred one thousand, four hundred forty-one".

Divisors: 1 3 3727 11181 100287461 300862383 373771367147 1121314101441