Search a number
-
+
1121320034 = 217311063871
BaseRepresentation
bin100001011010101…
…1111110001100010
32220010221221220122
41002311133301202
54244024220114
6303133440242
736534030422
oct10265376142
92803857818
101121320034
11525a5737a
12273640082
1314b406ba3
14a8ccc482
1568697e8e
hex42d5fc62

1121320034 has 16 divisors (see below), whose sum is σ = 1838370816. Its totient is φ = 510657600.

The previous prime is 1121320027. The next prime is 1121320037. The reversal of 1121320034 is 4300231211.

It is a super-2 number, since 2×11213200342 = 2514717237299522312, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a junction number, because it is equal to n+sod(n) for n = 1121319994 and 1121320021.

It is not an unprimeable number, because it can be changed into a prime (1121320037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 530882 + ... + 532989.

It is an arithmetic number, because the mean of its divisors is an integer number (114898176).

Almost surely, 21121320034 is an apocalyptic number.

1121320034 is a deficient number, since it is larger than the sum of its proper divisors (717050782).

1121320034 is a wasteful number, since it uses less digits than its factorization.

1121320034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1063921.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1121320034 is about 33486.1170337798. The cubic root of 1121320034 is about 1038.9066523764.

Adding to 1121320034 its reverse (4300231211), we get a palindrome (5421551245).

The spelling of 1121320034 in words is "one billion, one hundred twenty-one million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 17 31 34 62 527 1054 1063871 2127742 18085807 32980001 36171614 65960002 560660017 1121320034