| Base | Representation |
|---|---|
| bin | 110100001101110011… |
| … | …0000101111000100100 |
| 3 | 101201102200100220022012 |
| 4 | 1220123212011320210 |
| 5 | 3314121310320400 |
| 6 | 123302432253352 |
| 7 | 11046511203020 |
| oct | 1503346057044 |
| 9 | 351380326265 |
| 10 | 112132120100 |
| 11 | 43611727540 |
| 12 | 198949a1258 |
| 13 | a760152a30 |
| 14 | 55da431380 |
| 15 | 2db43a6d35 |
| hex | 1a1b985e24 |
112132120100 has 288 divisors, whose sum is σ = 329095603200. Its totient is φ = 32025715200.
The previous prime is 112132120069. The next prime is 112132120103. The reversal of 112132120100 is 1021231211.
It is a super-2 number, since 2×1121321201002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is not an unprimeable number, because it can be changed into a prime (112132120103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 13909871 + ... + 13917929.
Almost surely, 2112132120100 is an apocalyptic number.
112132120100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112132120100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164547801600).
112132120100 is an abundant number, since it is smaller than the sum of its proper divisors (216963483100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112132120100 is a wasteful number, since it uses less digits than its factorization.
112132120100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8243 (or 8236 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 112132120100 its reverse (1021231211), we get a palindrome (113153351311).
Subtracting from 112132120100 its reverse (1021231211), we obtain a square (111110888889 = 3333332).
It can be divided in two parts, 112132 and 120100, that added together give a palindrome (232232).
The spelling of 112132120100 in words is "one hundred twelve billion, one hundred thirty-two million, one hundred twenty thousand, one hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •