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112132201141 = 1031088662147
BaseRepresentation
bin110100001101110011…
…0011001101010110101
3101201102200112000110201
41220123212121222311
53314121320414031
6123302434120501
711046511661212
oct1503346315265
9351380460421
10112132201141
1143611782414
1219894a20131
13a76018089c
1455da452b09
152db43c0d61
hex1a1b999ab5

112132201141 has 4 divisors (see below), whose sum is σ = 113220863392. Its totient is φ = 111043538892.

The previous prime is 112132201133. The next prime is 112132201157. The reversal of 112132201141 is 141102231211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112132201141 - 23 = 112132201133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112132201171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 544330971 + ... + 544331176.

It is an arithmetic number, because the mean of its divisors is an integer number (28305215848).

Almost surely, 2112132201141 is an apocalyptic number.

It is an amenable number.

112132201141 is a deficient number, since it is larger than the sum of its proper divisors (1088662251).

112132201141 is a wasteful number, since it uses less digits than its factorization.

112132201141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1088662250.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 112132201141 its reverse (141102231211), we get a palindrome (253234432352).

The spelling of 112132201141 in words is "one hundred twelve billion, one hundred thirty-two million, two hundred one thousand, one hundred forty-one".

Divisors: 1 103 1088662147 112132201141