Base | Representation |
---|---|
bin | 11001011111101111010001… |
… | …001101010010111011001011 |
3 | 112201000201212021202110211012 |
4 | 121133233101031102323023 |
5 | 104144133242101321303 |
6 | 1034252455314154135 |
7 | 32422166654144234 |
oct | 3137572115227313 |
9 | 481021767673735 |
10 | 112132221120203 |
11 | 3280200a5a5639 |
12 | 106abb85b8294b |
13 | 4a7503b924c5b |
14 | 1d9932ac7408b |
15 | ce6c3a5435d8 |
hex | 65fbd1352ecb |
112132221120203 has 2 divisors, whose sum is σ = 112132221120204. Its totient is φ = 112132221120202.
The previous prime is 112132221120193. The next prime is 112132221120221. The reversal of 112132221120203 is 302021122231211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112132221120203 - 218 = 112132220858059 is a prime.
It is a super-2 number, since 2×1121322211202032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112132221120103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066110560101 + 56066110560102.
It is an arithmetic number, because the mean of its divisors is an integer number (56066110560102).
Almost surely, 2112132221120203 is an apocalyptic number.
112132221120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
112132221120203 is an equidigital number, since it uses as much as digits as its factorization.
112132221120203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 112132221120203 its reverse (302021122231211), we get a palindrome (414153343351414).
The spelling of 112132221120203 in words is "one hundred twelve trillion, one hundred thirty-two billion, two hundred twenty-one million, one hundred twenty thousand, two hundred three".
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