Base | Representation |
---|---|
bin | 10000010100010100100… |
… | …011000110101100110001 |
3 | 10222012100111111120020201 |
4 | 100110110203012230301 |
5 | 121332441242223212 |
6 | 2215044335235201 |
7 | 144004430013151 |
oct | 20242443065461 |
9 | 3865314446221 |
10 | 1121331211057 |
11 | 3a2610265642 |
12 | 1613a3678b01 |
13 | 819831c8155 |
14 | 3c3b64b6761 |
15 | 1e27d524b57 |
hex | 105148c6b31 |
1121331211057 has 2 divisors, whose sum is σ = 1121331211058. Its totient is φ = 1121331211056.
The previous prime is 1121331211037. The next prime is 1121331211129. The reversal of 1121331211057 is 7501121331211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1120921917696 + 409293361 = 1058736^2 + 20231^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121331211057 - 223 = 1121322822449 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121331211037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560665605528 + 560665605529.
It is an arithmetic number, because the mean of its divisors is an integer number (560665605529).
Almost surely, 21121331211057 is an apocalyptic number.
It is an amenable number.
1121331211057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121331211057 is an equidigital number, since it uses as much as digits as its factorization.
1121331211057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 28.
Adding to 1121331211057 its reverse (7501121331211), we get a palindrome (8622452542268).
The spelling of 1121331211057 in words is "one trillion, one hundred twenty-one billion, three hundred thirty-one million, two hundred eleven thousand, fifty-seven".
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