Search a number
-
+
112133202017 is a prime number
BaseRepresentation
bin110100001101110101…
…0001110000001100001
3101201102202101212102012
41220123222032001201
53314122044431032
6123302511402305
711046523330214
oct1503352160141
9351382355365
10112133202017
11436122a6391
1219895223395
13a760441315
1455da63377b
152db451c6b2
hex1a1ba8e061

112133202017 has 2 divisors, whose sum is σ = 112133202018. Its totient is φ = 112133202016.

The previous prime is 112133201981. The next prime is 112133202043. The reversal of 112133202017 is 710202331211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112128540736 + 4661281 = 334856^2 + 2159^2 .

It is a cyclic number.

It is not a de Polignac number, because 112133202017 - 222 = 112129007713 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112133201983 and 112133202001.

It is not a weakly prime, because it can be changed into another prime (112133205017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066601008 + 56066601009.

It is an arithmetic number, because the mean of its divisors is an integer number (56066601009).

Almost surely, 2112133202017 is an apocalyptic number.

It is an amenable number.

112133202017 is a deficient number, since it is larger than the sum of its proper divisors (1).

112133202017 is an equidigital number, since it uses as much as digits as its factorization.

112133202017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 112133202017 its reverse (710202331211), we get a palindrome (822335533228).

The spelling of 112133202017 in words is "one hundred twelve billion, one hundred thirty-three million, two hundred two thousand, seventeen".