Base | Representation |
---|---|
bin | 110100001101110101… |
… | …0001110000001100001 |
3 | 101201102202101212102012 |
4 | 1220123222032001201 |
5 | 3314122044431032 |
6 | 123302511402305 |
7 | 11046523330214 |
oct | 1503352160141 |
9 | 351382355365 |
10 | 112133202017 |
11 | 436122a6391 |
12 | 19895223395 |
13 | a760441315 |
14 | 55da63377b |
15 | 2db451c6b2 |
hex | 1a1ba8e061 |
112133202017 has 2 divisors, whose sum is σ = 112133202018. Its totient is φ = 112133202016.
The previous prime is 112133201981. The next prime is 112133202043. The reversal of 112133202017 is 710202331211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112128540736 + 4661281 = 334856^2 + 2159^2 .
It is a cyclic number.
It is not a de Polignac number, because 112133202017 - 222 = 112129007713 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112133201983 and 112133202001.
It is not a weakly prime, because it can be changed into another prime (112133205017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066601008 + 56066601009.
It is an arithmetic number, because the mean of its divisors is an integer number (56066601009).
Almost surely, 2112133202017 is an apocalyptic number.
It is an amenable number.
112133202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
112133202017 is an equidigital number, since it uses as much as digits as its factorization.
112133202017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 112133202017 its reverse (710202331211), we get a palindrome (822335533228).
The spelling of 112133202017 in words is "one hundred twelve billion, one hundred thirty-three million, two hundred two thousand, seventeen".
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