Base | Representation |
---|---|
bin | 1010001100101100111011… |
… | …0000011000101111011011 |
3 | 1110200222120111010221210001 |
4 | 2203023032300120233123 |
5 | 2432204401324331212 |
6 | 35503200111233431 |
7 | 2235064566352615 |
oct | 243131660305733 |
9 | 43628514127701 |
10 | 11213333433307 |
11 | 3633603434985 |
12 | 1311276818877 |
13 | 634549c1a625 |
14 | 2aaa2a3b9db5 |
15 | 146a40495657 |
hex | a32cec18bdb |
11213333433307 has 2 divisors, whose sum is σ = 11213333433308. Its totient is φ = 11213333433306.
The previous prime is 11213333433299. The next prime is 11213333433349. The reversal of 11213333433307 is 70333433331211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11213333433307 - 23 = 11213333433299 is a prime.
It is not a weakly prime, because it can be changed into another prime (11213333433707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606666716653 + 5606666716654.
It is an arithmetic number, because the mean of its divisors is an integer number (5606666716654).
Almost surely, 211213333433307 is an apocalyptic number.
11213333433307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213333433307 is an equidigital number, since it uses as much as digits as its factorization.
11213333433307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 122472, while the sum is 37.
Adding to 11213333433307 its reverse (70333433331211), we get a palindrome (81546766764518).
The spelling of 11213333433307 in words is "eleven trillion, two hundred thirteen billion, three hundred thirty-three million, four hundred thirty-three thousand, three hundred seven".
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