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11213541305255 = 53517637676503
BaseRepresentation
bin1010001100101101101100…
…1001010110101110100111
31110201000002222021221111002
42203023123021112232213
52432210313033232010
635503232454503515
72235103002264362
oct243133311265647
943630088257432
1011213541305255
1136336aa804183
121311314364b9b
13634580ccc993
142aaa49c4b0d9
15146a538571a5
hexa32db256ba7

11213541305255 has 8 divisors (see below), whose sum is σ = 13460075646432. Its totient is φ = 8968282324128.

The previous prime is 11213541305237. The next prime is 11213541305269. The reversal of 11213541305255 is 55250314531211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11213541305255 - 224 = 11213524528039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 318820667 + ... + 318855836.

It is an arithmetic number, because the mean of its divisors is an integer number (1682509455804).

Almost surely, 211213541305255 is an apocalyptic number.

11213541305255 is a deficient number, since it is larger than the sum of its proper divisors (2246534341177).

11213541305255 is an equidigital number, since it uses as much as digits as its factorization.

11213541305255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637680025.

The product of its (nonzero) digits is 90000, while the sum is 38.

Adding to 11213541305255 its reverse (55250314531211), we get a palindrome (66463855836466).

The spelling of 11213541305255 in words is "eleven trillion, two hundred thirteen billion, five hundred forty-one million, three hundred five thousand, two hundred fifty-five".

Divisors: 1 5 3517 17585 637676503 3188382515 2242708261051 11213541305255