Base | Representation |
---|---|
bin | 1010001100101101101110… |
… | …1010101110100010001001 |
3 | 1110201000010120202101211122 |
4 | 2203023123222232202021 |
5 | 2432210322303203023 |
6 | 35503233410205025 |
7 | 2235103136531453 |
oct | 243133352564211 |
9 | 43630116671748 |
10 | 11213550053513 |
11 | 3633704739945 |
12 | 1311317283775 |
13 | 634582a73872 |
14 | 2aaa4b0872d3 |
15 | 146a544d42c8 |
hex | a32dbaae889 |
11213550053513 has 2 divisors, whose sum is σ = 11213550053514. Its totient is φ = 11213550053512.
The previous prime is 11213550053491. The next prime is 11213550053549. The reversal of 11213550053513 is 31535005531211.
11213550053513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10197784399609 + 1015765653904 = 3193397^2 + 1007852^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213550053513 - 228 = 11213281618057 is a prime.
It is not a weakly prime, because it can be changed into another prime (11213550053593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606775026756 + 5606775026757.
It is an arithmetic number, because the mean of its divisors is an integer number (5606775026757).
Almost surely, 211213550053513 is an apocalyptic number.
It is an amenable number.
11213550053513 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213550053513 is an equidigital number, since it uses as much as digits as its factorization.
11213550053513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33750, while the sum is 35.
Adding to 11213550053513 its reverse (31535005531211), we get a palindrome (42748555584724).
The spelling of 11213550053513 in words is "eleven trillion, two hundred thirteen billion, five hundred fifty million, fifty-three thousand, five hundred thirteen".
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