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1121404332 = 223167559583
BaseRepresentation
bin100001011010111…
…0100010110101100
32220011010020112210
41002311310112230
54244034414312
6303135330420
736534531246
oct10265642654
92804106483
101121404332
11526004744
12273680a10
1314b436379
14a8d11096
15686b2e3c
hex42d745ac

1121404332 has 24 divisors (see below), whose sum is σ = 2632283136. Its totient is φ = 371562448.

The previous prime is 1121404309. The next prime is 1121404343. The reversal of 1121404332 is 2334041211.

It is a junction number, because it is equal to n+sod(n) for n = 1121404299 and 1121404308.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 277788 + ... + 281795.

It is an arithmetic number, because the mean of its divisors is an integer number (109678464).

Almost surely, 21121404332 is an apocalyptic number.

1121404332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1121404332 is an abundant number, since it is smaller than the sum of its proper divisors (1510878804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121404332 is a wasteful number, since it uses less digits than its factorization.

1121404332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 559757 (or 559755 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1121404332 is about 33487.3757108556. The cubic root of 1121404332 is about 1038.9326858476.

Adding to 1121404332 its reverse (2334041211), we get a palindrome (3455445543).

The spelling of 1121404332 in words is "one billion, one hundred twenty-one million, four hundred four thousand, three hundred thirty-two".

Divisors: 1 2 3 4 6 12 167 334 501 668 1002 2004 559583 1119166 1678749 2238332 3357498 6714996 93450361 186900722 280351083 373801444 560702166 1121404332