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1121406731441 is a prime number
BaseRepresentation
bin10000010100011001000…
…011001100010010110001
310222012112202121101201222
4100110121003030102301
5121333120110401231
62215100034034425
7144006334641203
oct20243103142261
93865482541658
101121406731441
113a2649957187
12161404a18a15
1381995a4a579
143c3c2534773
151e284e9127b
hex105190cc4b1

1121406731441 has 2 divisors, whose sum is σ = 1121406731442. Its totient is φ = 1121406731440.

The previous prime is 1121406731429. The next prime is 1121406731503. The reversal of 1121406731441 is 1441376041211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 698294209600 + 423112521841 = 835640^2 + 650471^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121406731441 - 222 = 1121402537137 is a prime.

It is a super-4 number, since 4×11214067314414 (a number of 49 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1121406731411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560703365720 + 560703365721.

It is an arithmetic number, because the mean of its divisors is an integer number (560703365721).

Almost surely, 21121406731441 is an apocalyptic number.

It is an amenable number.

1121406731441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121406731441 is an equidigital number, since it uses as much as digits as its factorization.

1121406731441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 35.

The spelling of 1121406731441 in words is "one trillion, one hundred twenty-one billion, four hundred six million, seven hundred thirty-one thousand, four hundred forty-one".