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1121410141211 = 9901113262311
BaseRepresentation
bin10000010100011001010…
…000001100110000011011
310222012120000000122001202
4100110121100030300123
5121333121444004321
62215100235104415
7144006405632213
oct20243120146033
93865500018052
101121410141211
113a2650875a78
12161405ba210b
1381996672599
143c3c2b81243
151e28541670b
hex1051940cc1b

1121410141211 has 4 divisors (see below), whose sum is σ = 1121523413424. Its totient is φ = 1121296869000.

The previous prime is 1121410141207. The next prime is 1121410141253.

1121410141211 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1121410141211 - 22 = 1121410141207 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1121410143211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56621255 + ... + 56641056.

It is an arithmetic number, because the mean of its divisors is an integer number (280380853356).

Almost surely, 21121410141211 is an apocalyptic number.

1121410141211 is a deficient number, since it is larger than the sum of its proper divisors (113272213).

1121410141211 is an equidigital number, since it uses as much as digits as its factorization.

1121410141211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113272212.

The product of its (nonzero) digits is 64, while the sum is 20.

It can be divided in two parts, 1121410 and 141211, that added together give a palindrome (1262621).

The spelling of 1121410141211 in words is "one trillion, one hundred twenty-one billion, four hundred ten million, one hundred forty-one thousand, two hundred eleven".

Divisors: 1 9901 113262311 1121410141211