112142001113 has 2 divisors, whose sum is σ = 112142001114. Its totient is φ = 112142001112.

The previous prime is 112142001091. The next prime is 112142001149. The reversal of 112142001113 is 311100241211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61805937664 + 50336063449 = 248608^2 + 224357^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112142001113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112142001091 and 112142001100.

It is not a weakly prime, because it can be changed into another prime (112142001173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56071000556 + 56071000557.

It is an arithmetic number, because the mean of its divisors is an integer number (56071000557).

Almost surely, 2^112142001113 is an apocalyptic number.

It is an amenable number.

112142001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112142001113 is an equidigital number, since it uses as much as digits as its factorization.

112142001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 112142001113 its reverse (311100241211), we get a palindrome (423242242324).

The spelling of 112142001113 in words is "one hundred twelve billion, one hundred forty-two million, one thousand, one hundred thirteen".