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1121420404081 is a prime number
BaseRepresentation
bin10000010100011001110…
…111010110010101110001
310222012120201100001002001
4100110121313112111301
5121333132110412311
62215101243054001
7144006562105135
oct20243167262561
93865521301061
101121420404081
113a265664568a
12161409511301
13819988269a3
143c3c42933c5
151e2862924c1
hex10519dd6571

1121420404081 has 2 divisors, whose sum is σ = 1121420404082. Its totient is φ = 1121420404080.

The previous prime is 1121420404061. The next prime is 1121420404123. The reversal of 1121420404081 is 1804040241211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 730826653456 + 390593750625 = 854884^2 + 624975^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121420404081 - 213 = 1121420395889 is a prime.

It is a super-2 number, since 2×11214204040812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1121420404001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560710202040 + 560710202041.

It is an arithmetic number, because the mean of its divisors is an integer number (560710202041).

Almost surely, 21121420404081 is an apocalyptic number.

It is an amenable number.

1121420404081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121420404081 is an equidigital number, since it uses as much as digits as its factorization.

1121420404081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2048, while the sum is 28.

Adding to 1121420404081 its reverse (1804040241211), we get a palindrome (2925460645292).

The spelling of 1121420404081 in words is "one trillion, one hundred twenty-one billion, four hundred twenty million, four hundred four thousand, eighty-one".