Base | Representation |
---|---|
bin | 1010001100110000010000… |
… | …1100101001011011010110 |
3 | 1110201001212222020222220002 |
4 | 2203030010030221123112 |
5 | 2432213220342043014 |
6 | 35503425100411302 |
7 | 2235126034343321 |
oct | 243140414513326 |
9 | 43631788228802 |
10 | 11214230034134 |
11 | 3633a235553a6 |
12 | 1311486b46b32 |
13 | 6346608c3a6a |
14 | 2aaab34cd7b8 |
15 | 146a9404edde |
hex | a33043296d6 |
11214230034134 has 4 divisors (see below), whose sum is σ = 16821345051204. Its totient is φ = 5607115017066.
The previous prime is 11214230034113. The next prime is 11214230034179. The reversal of 11214230034134 is 43143003241211.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11214230034097 and 11214230034106.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2803557508532 + ... + 2803557508535.
It is an arithmetic number, because the mean of its divisors is an integer number (4205336262801).
Almost surely, 211214230034134 is an apocalyptic number.
11214230034134 is a deficient number, since it is larger than the sum of its proper divisors (5607115017070).
11214230034134 is an equidigital number, since it uses as much as digits as its factorization.
11214230034134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5607115017069.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11214230034134 its reverse (43143003241211), we get a palindrome (54357233275345).
The spelling of 11214230034134 in words is "eleven trillion, two hundred fourteen billion, two hundred thirty million, thirty-four thousand, one hundred thirty-four".
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