Base | Representation |
---|---|
bin | 11001011111111000110100… |
… | …110101011100110000111011 |
3 | 112201001201100102101212020201 |
4 | 121133320310311130300323 |
5 | 104144320301011301433 |
6 | 1034301313435503031 |
7 | 32423012154512062 |
oct | 3137706465346073 |
9 | 481051312355221 |
10 | 112142482525243 |
11 | 328063a5923075 |
12 | 106b1b6a5b7a77 |
13 | 4a75cb5819061 |
14 | 1d99a21a011d9 |
15 | ce713b339a7d |
hex | 65fe34d5cc3b |
112142482525243 has 2 divisors, whose sum is σ = 112142482525244. Its totient is φ = 112142482525242.
The previous prime is 112142482525121. The next prime is 112142482525267. The reversal of 112142482525243 is 342525284241211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112142482525243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112142482525193 and 112142482525202.
It is not a weakly prime, because it can be changed into another prime (112142482535243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56071241262621 + 56071241262622.
It is an arithmetic number, because the mean of its divisors is an integer number (56071241262622).
Almost surely, 2112142482525243 is an apocalyptic number.
112142482525243 is a deficient number, since it is larger than the sum of its proper divisors (1).
112142482525243 is an equidigital number, since it uses as much as digits as its factorization.
112142482525243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1228800, while the sum is 46.
The spelling of 112142482525243 in words is "one hundred twelve trillion, one hundred forty-two billion, four hundred eighty-two million, five hundred twenty-five thousand, two hundred forty-three".
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