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112142482525243 is a prime number
BaseRepresentation
bin11001011111111000110100…
…110101011100110000111011
3112201001201100102101212020201
4121133320310311130300323
5104144320301011301433
61034301313435503031
732423012154512062
oct3137706465346073
9481051312355221
10112142482525243
11328063a5923075
12106b1b6a5b7a77
134a75cb5819061
141d99a21a011d9
15ce713b339a7d
hex65fe34d5cc3b

112142482525243 has 2 divisors, whose sum is σ = 112142482525244. Its totient is φ = 112142482525242.

The previous prime is 112142482525121. The next prime is 112142482525267. The reversal of 112142482525243 is 342525284241211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112142482525243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112142482525193 and 112142482525202.

It is not a weakly prime, because it can be changed into another prime (112142482535243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56071241262621 + 56071241262622.

It is an arithmetic number, because the mean of its divisors is an integer number (56071241262622).

Almost surely, 2112142482525243 is an apocalyptic number.

112142482525243 is a deficient number, since it is larger than the sum of its proper divisors (1).

112142482525243 is an equidigital number, since it uses as much as digits as its factorization.

112142482525243 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1228800, while the sum is 46.

The spelling of 112142482525243 in words is "one hundred twelve trillion, one hundred forty-two billion, four hundred eighty-two million, five hundred twenty-five thousand, two hundred forty-three".