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11214335303 = 13189639551
BaseRepresentation
bin10100111000110110…
…10010110101000111
31001221112202020222222
422130123102311013
5140431332212203
65052442042555
7544621164053
oct123433226507
931845666888
1011214335303
114835222106
12220b7a945b
131099460882
14785544c63
154597cb038
hex29c6d2d47

11214335303 has 8 divisors (see below), whose sum is σ = 11302384896. Its totient is φ = 11126323000.

The previous prime is 11214335299. The next prime is 11214335309. The reversal of 11214335303 is 30353341211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11214335303 - 22 = 11214335299 is a prime.

It is a super-2 number, since 2×112143353032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11214335309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1169378 + ... + 1178928.

It is an arithmetic number, because the mean of its divisors is an integer number (1412798112).

Almost surely, 211214335303 is an apocalyptic number.

11214335303 is a deficient number, since it is larger than the sum of its proper divisors (88049593).

11214335303 is an equidigital number, since it uses as much as digits as its factorization.

11214335303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18645.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 11214335303 its reverse (30353341211), we get a palindrome (41567676514).

The spelling of 11214335303 in words is "eleven billion, two hundred fourteen million, three hundred thirty-five thousand, three hundred three".

Divisors: 1 131 8963 9551 1174153 1251181 85605613 11214335303