Base | Representation |
---|---|
bin | 11001011111111001101100… |
… | …110101010001011110111101 |
3 | 112201001210202220012021122010 |
4 | 121133321230311101132331 |
5 | 104144324212013100013 |
6 | 1034301551000041433 |
7 | 32423044353112503 |
oct | 3137715465213675 |
9 | 481053686167563 |
10 | 112143422003133 |
11 | 32806838169784 |
12 | 106b2191163279 |
13 | 4a76105355731 |
14 | 1d99ab06b6673 |
15 | ce7193a637c3 |
hex | 65fe6cd517bd |
112143422003133 has 4 divisors (see below), whose sum is σ = 149524562670848. Its totient is φ = 74762281335420.
The previous prime is 112143422003131. The next prime is 112143422003167. The reversal of 112143422003133 is 331300224341211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 112143422003133 - 21 = 112143422003131 is a prime.
It is a super-2 number, since 2×1121434220031332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 112143422003133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112143422003131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18690570333853 + ... + 18690570333858.
It is an arithmetic number, because the mean of its divisors is an integer number (37381140667712).
Almost surely, 2112143422003133 is an apocalyptic number.
It is an amenable number.
112143422003133 is a deficient number, since it is larger than the sum of its proper divisors (37381140667715).
112143422003133 is an equidigital number, since it uses as much as digits as its factorization.
112143422003133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37381140667714.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 112143422003133 its reverse (331300224341211), we get a palindrome (443443646344344).
The spelling of 112143422003133 in words is "one hundred twelve trillion, one hundred forty-three billion, four hundred twenty-two million, three thousand, one hundred thirty-three".
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