11215048703 has 4 divisors (see below), whose sum is σ = 11216441208. Its totient is φ = 11213656200.

The previous prime is 11215048697. The next prime is 11215048753. The reversal of 11215048703 is 30784051211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11215048703 - 2¹⁴ = 11215032319 is a prime.

It is a super-3 number, since 3×11215048703³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11215048703.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11215048753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 684101 + ... + 700302.

It is an arithmetic number, because the mean of its divisors is an integer number (2804110302).

Almost surely, 2^11215048703 is an apocalyptic number.

11215048703 is a deficient number, since it is larger than the sum of its proper divisors (1392505).

11215048703 is an equidigital number, since it uses as much as digits as its factorization.

11215048703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1392504.

The product of its (nonzero) digits is 6720, while the sum is 32.

Adding to 11215048703 its reverse (30784051211), we get a palindrome (41999099914).

The spelling of 11215048703 in words is "eleven billion, two hundred fifteen million, forty-eight thousand, seven hundred three".