Base | Representation |
---|---|
bin | 110100001110100010… |
… | …1011110011100110011 |
3 | 101201111102102020202111 |
4 | 1220131011132130303 |
5 | 3314144210440103 |
6 | 123305124230151 |
7 | 11050233553612 |
oct | 1503505363463 |
9 | 351442366674 |
10 | 112157124403 |
11 | 43624855655 |
12 | 198a123b357 |
13 | a765398b8c |
14 | 55dd89d879 |
15 | 2db669586d |
hex | 1a1d15e733 |
112157124403 has 2 divisors, whose sum is σ = 112157124404. Its totient is φ = 112157124402.
The previous prime is 112157124371. The next prime is 112157124481. The reversal of 112157124403 is 304421751211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112157124403 - 25 = 112157124371 is a prime.
It is not a weakly prime, because it can be changed into another prime (112157124493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56078562201 + 56078562202.
It is an arithmetic number, because the mean of its divisors is an integer number (56078562202).
Almost surely, 2112157124403 is an apocalyptic number.
112157124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
112157124403 is an equidigital number, since it uses as much as digits as its factorization.
112157124403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 112157124403 its reverse (304421751211), we get a palindrome (416578875614).
The spelling of 112157124403 in words is "one hundred twelve billion, one hundred fifty-seven million, one hundred twenty-four thousand, four hundred three".
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