Base | Representation |
---|---|
bin | 1010001100111011001001… |
… | …0001100100101100111011 |
3 | 1110201100102111202010200212 |
4 | 2203032302101210230323 |
5 | 2432240211020423313 |
6 | 35505030545421335 |
7 | 2235261306406205 |
oct | 243166221445473 |
9 | 43640374663625 |
10 | 11217150561083 |
11 | 3635192074535 |
12 | 1311b6103a84b |
13 | 634a079a0a0c |
14 | 2aacad329775 |
15 | 146bb56463a8 |
hex | a33b2464b3b |
11217150561083 has 2 divisors, whose sum is σ = 11217150561084. Its totient is φ = 11217150561082.
The previous prime is 11217150561049. The next prime is 11217150561163. The reversal of 11217150561083 is 38016505171211.
11217150561083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11217150561083 - 220 = 11217149512507 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11217150561083.
It is not a weakly prime, because it can be changed into another prime (11217150561013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5608575280541 + 5608575280542.
It is an arithmetic number, because the mean of its divisors is an integer number (5608575280542).
Almost surely, 211217150561083 is an apocalyptic number.
11217150561083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11217150561083 is an equidigital number, since it uses as much as digits as its factorization.
11217150561083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 41.
The spelling of 11217150561083 in words is "eleven trillion, two hundred seventeen billion, one hundred fifty million, five hundred sixty-one thousand, eighty-three".
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