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11217150561083 is a prime number
BaseRepresentation
bin1010001100111011001001…
…0001100100101100111011
31110201100102111202010200212
42203032302101210230323
52432240211020423313
635505030545421335
72235261306406205
oct243166221445473
943640374663625
1011217150561083
113635192074535
121311b6103a84b
13634a079a0a0c
142aacad329775
15146bb56463a8
hexa33b2464b3b

11217150561083 has 2 divisors, whose sum is σ = 11217150561084. Its totient is φ = 11217150561082.

The previous prime is 11217150561049. The next prime is 11217150561163. The reversal of 11217150561083 is 38016505171211.

11217150561083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11217150561083 - 220 = 11217149512507 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11217150561083.

It is not a weakly prime, because it can be changed into another prime (11217150561013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5608575280541 + 5608575280542.

It is an arithmetic number, because the mean of its divisors is an integer number (5608575280542).

Almost surely, 211217150561083 is an apocalyptic number.

11217150561083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11217150561083 is an equidigital number, since it uses as much as digits as its factorization.

11217150561083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 41.

The spelling of 11217150561083 in words is "eleven trillion, two hundred seventeen billion, one hundred fifty million, five hundred sixty-one thousand, eighty-three".