Base | Representation |
---|---|
bin | 11001100000101110011111… |
… | …110110111001100100100110 |
3 | 112201021020002202122010211011 |
4 | 121200232133312321210212 |
5 | 104201241312314023332 |
6 | 1034344004205132434 |
7 | 32430122246440144 |
oct | 3140563766714446 |
9 | 481236082563734 |
10 | 112200112642342 |
11 | 3282888959901a |
12 | 1070117285a11a |
13 | 4a7b56b2a396a |
14 | 1d9c72b834594 |
15 | ce88b09b4e47 |
hex | 660b9fdb9926 |
112200112642342 has 4 divisors (see below), whose sum is σ = 168300168963516. Its totient is φ = 56100056321170.
The previous prime is 112200112642297. The next prime is 112200112642523. The reversal of 112200112642342 is 243246211002211.
112200112642342 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1122001126423422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28050028160584 + ... + 28050028160587.
It is an arithmetic number, because the mean of its divisors is an integer number (42075042240879).
Almost surely, 2112200112642342 is an apocalyptic number.
112200112642342 is a deficient number, since it is larger than the sum of its proper divisors (56100056321174).
112200112642342 is an equidigital number, since it uses as much as digits as its factorization.
112200112642342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56100056321173.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 112200112642342 its reverse (243246211002211), we get a palindrome (355446323644553).
The spelling of 112200112642342 in words is "one hundred twelve trillion, two hundred billion, one hundred twelve million, six hundred forty-two thousand, three hundred forty-two".
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