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11220022431433 is a prime number
BaseRepresentation
bin1010001101000101110101…
…1100111000111011001001
31110201121211122200021012101
42203101131130320323021
52432312101220301213
635510223535513401
72235422421041104
oct243213534707311
943647748607171
1011220022431433
113636426180202
121312622988861
13635074972b9a
142ab0a28db73b
15146cd282abdd
hexa345d738ec9

11220022431433 has 2 divisors, whose sum is σ = 11220022431434. Its totient is φ = 11220022431432.

The previous prime is 11220022431427. The next prime is 11220022431437. The reversal of 11220022431433 is 33413422002211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11210362883344 + 9659548089 = 3348188^2 + 98283^2 .

It is a cyclic number.

It is not a de Polignac number, because 11220022431433 - 213 = 11220022423241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11220022431437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610011215716 + 5610011215717.

It is an arithmetic number, because the mean of its divisors is an integer number (5610011215717).

Almost surely, 211220022431433 is an apocalyptic number.

It is an amenable number.

11220022431433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11220022431433 is an equidigital number, since it uses as much as digits as its factorization.

11220022431433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 11220022431433 its reverse (33413422002211), we get a palindrome (44633444433644).

The spelling of 11220022431433 in words is "eleven trillion, two hundred twenty billion, twenty-two million, four hundred thirty-one thousand, four hundred thirty-three".