Base | Representation |
---|---|
bin | 11001100000101111100000… |
… | …101110101100100100111011 |
3 | 112201021022220121120222221120 |
4 | 121200233200232230210323 |
5 | 104201301024424323003 |
6 | 1034344304204440323 |
7 | 32430161233430466 |
oct | 3140574056544473 |
9 | 481238817528846 |
10 | 112201201011003 |
11 | 32829297989555 |
12 | 107014172490a3 |
13 | 4a7b6b29113a0 |
14 | 1d9c7d21c62dd |
15 | ce89262ee853 |
hex | 660be0bac93b |
112201201011003 has 32 divisors (see below), whose sum is σ = 163520180474112. Its totient is φ = 68013785980800.
The previous prime is 112201201010989. The next prime is 112201201011023. The reversal of 112201201011003 is 300110102102211.
It is not a de Polignac number, because 112201201011003 - 217 = 112201200879931 is a prime.
It is not an unprimeable number, because it can be changed into a prime (112201201011023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 69917008 + ... + 71503778.
It is an arithmetic number, because the mean of its divisors is an integer number (5110005639816).
Almost surely, 2112201201011003 is an apocalyptic number.
112201201011003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
112201201011003 is a deficient number, since it is larger than the sum of its proper divisors (51318979463109).
112201201011003 is a wasteful number, since it uses less digits than its factorization.
112201201011003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1613915.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 112201201011003 its reverse (300110102102211), we get a palindrome (412311303113214).
The spelling of 112201201011003 in words is "one hundred twelve trillion, two hundred one billion, two hundred one million, eleven thousand, three".
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