Base | Representation |
---|---|
bin | 1010001101000110001101… |
… | …0100111001100100001000 |
3 | 1110201122002112011002010110 |
4 | 2203101203110321210020 |
5 | 2432312301434001300 |
6 | 35510241420314320 |
7 | 2235425025622440 |
oct | 243214324714410 |
9 | 43648075132113 |
10 | 11220121000200 |
11 | 36364768843a2 |
12 | 131264b9a29a0 |
13 | 63508c2050b8 |
14 | 2ab0b1a39120 |
15 | 146cdb2eb550 |
hex | a3463539908 |
11220121000200 has 192 divisors, whose sum is σ = 39816782991360. Its totient is φ = 2560373464320.
The previous prime is 11220121000183. The next prime is 11220121000201. The reversal of 11220121000200 is 200012102211.
It is a super-2 number, since 2×112201210002002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is not an unprimeable number, because it can be changed into a prime (11220121000201) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 348859 + ... + 4749941.
It is an arithmetic number, because the mean of its divisors is an integer number (207379078080).
Almost surely, 211220121000200 is an apocalyptic number.
11220121000200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11220121000200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19908391495680).
11220121000200 is an abundant number, since it is smaller than the sum of its proper divisors (28596661991160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11220121000200 is a wasteful number, since it uses less digits than its factorization.
11220121000200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4401716 (or 4401707 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 11220121000200 its reverse (200012102211), we get a palindrome (11420133102411).
It can be divided in two parts, 1122012 and 1000200, that added together give a palindrome (2122212).
The spelling of 11220121000200 in words is "eleven trillion, two hundred twenty billion, one hundred twenty-one million, two hundred", and thus it is an aban number.
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