Base | Representation |
---|---|
bin | 10000010100111101001… |
… | …101110101111010100011 |
3 | 10222021010001100121000211 |
4 | 100110331031311322203 |
5 | 121340340424100024 |
6 | 2215240151154551 |
7 | 144030353262664 |
oct | 20247515657243 |
9 | 3867101317024 |
10 | 1122013503139 |
11 | 3a293040a7a1 |
12 | 161554075a57 |
13 | 81a61677489 |
14 | 3c43cd6136b |
15 | 1e2bd39a594 |
hex | 1053d375ea3 |
1122013503139 has 2 divisors, whose sum is σ = 1122013503140. Its totient is φ = 1122013503138.
The previous prime is 1122013503103. The next prime is 1122013503157. The reversal of 1122013503139 is 9313053102211.
It is a strong prime.
It is an emirp because it is prime and its reverse (9313053102211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1122013503139 - 29 = 1122013502627 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1122013503139.
It is not a weakly prime, because it can be changed into another prime (1122013503179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561006751569 + 561006751570.
It is an arithmetic number, because the mean of its divisors is an integer number (561006751570).
Almost surely, 21122013503139 is an apocalyptic number.
1122013503139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122013503139 is an equidigital number, since it uses as much as digits as its factorization.
1122013503139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 1122013503139 in words is "one trillion, one hundred twenty-two billion, thirteen million, five hundred three thousand, one hundred thirty-nine".
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