Base | Representation |
---|---|
bin | 10000010101000100010… |
… | …110011100110001010001 |
3 | 10222021102101120211012011 |
4 | 100111010112130301101 |
5 | 121341112044344303 |
6 | 2215300104502521 |
7 | 144033335552203 |
oct | 20250426346121 |
9 | 3867371524164 |
10 | 1122133199953 |
11 | 3a2991a34787 |
12 | 16158817aa41 |
13 | 81a803c63ac |
14 | 3c450bdc773 |
15 | 1e2c8b4116d |
hex | 1054459cc51 |
1122133199953 has 2 divisors, whose sum is σ = 1122133199954. Its totient is φ = 1122133199952.
The previous prime is 1122133199933. The next prime is 1122133200017. The reversal of 1122133199953 is 3599913312211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 966784495504 + 155348704449 = 983252^2 + 394143^2 .
It is a cyclic number.
It is not a de Polignac number, because 1122133199953 - 221 = 1122131102801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1122133199897 and 1122133199906.
It is not a weakly prime, because it can be changed into another prime (1122133199923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561066599976 + 561066599977.
It is an arithmetic number, because the mean of its divisors is an integer number (561066599977).
Almost surely, 21122133199953 is an apocalyptic number.
It is an amenable number.
1122133199953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122133199953 is an equidigital number, since it uses as much as digits as its factorization.
1122133199953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 393660, while the sum is 49.
The spelling of 1122133199953 in words is "one trillion, one hundred twenty-two billion, one hundred thirty-three million, one hundred ninety-nine thousand, nine hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •