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112222540433 is a prime number
BaseRepresentation
bin110100010000011111…
…1000001001010010001
3101201122222111201200102
41220200333001022101
53314312432243213
6123315422302145
711051656566113
oct1504077011221
9351588451612
10112222540433
1143658775693
12198bb127955
13a775ac10a3
14560844b3b3
152dbc2b8158
hex1a20fc1291

112222540433 has 2 divisors, whose sum is σ = 112222540434. Its totient is φ = 112222540432.

The previous prime is 112222540429. The next prime is 112222540457. The reversal of 112222540433 is 334045222211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98224574464 + 13997965969 = 313408^2 + 118313^2 .

It is a cyclic number.

It is not a de Polignac number, because 112222540433 - 22 = 112222540429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112222540396 and 112222540405.

It is not a weakly prime, because it can be changed into another prime (112222540333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56111270216 + 56111270217.

It is an arithmetic number, because the mean of its divisors is an integer number (56111270217).

Almost surely, 2112222540433 is an apocalyptic number.

It is an amenable number.

112222540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112222540433 is an equidigital number, since it uses as much as digits as its factorization.

112222540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 112222540433 its reverse (334045222211), we get a palindrome (446267762644).

The spelling of 112222540433 in words is "one hundred twelve billion, two hundred twenty-two million, five hundred forty thousand, four hundred thirty-three".