Base | Representation |
---|---|
bin | 11001100001001011011000… |
… | …110000011001101001111101 |
3 | 112201101012011120001100021221 |
4 | 121201023120300121221331 |
5 | 104202243324243324013 |
6 | 1034410134213553341 |
7 | 32432301034636522 |
oct | 3141133060315175 |
9 | 481335146040257 |
10 | 112231132011133 |
11 | 3283aa571849a3 |
12 | 1070718b045851 |
13 | 4a814728c7c55 |
14 | 1da00313cd149 |
15 | ce95c8d4908d |
hex | 6612d8c19a7d |
112231132011133 has 8 divisors (see below), whose sum is σ = 112553438459000. Its totient is φ = 111908829719808.
The previous prime is 112231132011127. The next prime is 112231132011191. The reversal of 112231132011133 is 331110231132211.
It can be written as a sum of positive squares in 4 ways, for example, as 17593217858329 + 94637914152804 = 4194427^2 + 9728202^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112231132011133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 112231132011098 and 112231132011107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112231132012133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57819985 + ... + 59729497.
It is an arithmetic number, because the mean of its divisors is an integer number (14069179807375).
Almost surely, 2112231132011133 is an apocalyptic number.
It is an amenable number.
112231132011133 is a deficient number, since it is larger than the sum of its proper divisors (322306447867).
112231132011133 is a wasteful number, since it uses less digits than its factorization.
112231132011133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2078271.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 112231132011133 its reverse (331110231132211), we get a palindrome (443341363143344).
The spelling of 112231132011133 in words is "one hundred twelve trillion, two hundred thirty-one billion, one hundred thirty-two million, eleven thousand, one hundred thirty-three".
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