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112234132433 is a prime number
BaseRepresentation
bin110100010000110101…
…1001111001111010001
3101201200210022122220202
41220201223033033101
53314323414214213
6123320514544545
711052160246043
oct1504153171721
9351623278822
10112234132433
1143664272955
1219902b98155
13a77831c467
145609bc7a93
152dbd307b58
hex1a21acf3d1

112234132433 has 2 divisors, whose sum is σ = 112234132434. Its totient is φ = 112234132432.

The previous prime is 112234132427. The next prime is 112234132441. The reversal of 112234132433 is 334231432211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91141798609 + 21092333824 = 301897^2 + 145232^2 .

It is a cyclic number.

It is not a de Polignac number, because 112234132433 - 28 = 112234132177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112234132396 and 112234132405.

It is not a weakly prime, because it can be changed into another prime (112234132403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56117066216 + 56117066217.

It is an arithmetic number, because the mean of its divisors is an integer number (56117066217).

Almost surely, 2112234132433 is an apocalyptic number.

It is an amenable number.

112234132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112234132433 is an equidigital number, since it uses as much as digits as its factorization.

112234132433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 29.

Adding to 112234132433 its reverse (334231432211), we get a palindrome (446465564644).

The spelling of 112234132433 in words is "one hundred twelve billion, two hundred thirty-four million, one hundred thirty-two thousand, four hundred thirty-three".