Base | Representation |
---|---|
bin | 10100111010000000… |
… | …01011101101100001 |
3 | 1001222012221112222102 |
4 | 22131000023231201 |
5 | 140441321133343 |
6 | 5053425220145 |
7 | 545066321012 |
oct | 123500135541 |
9 | 31865845872 |
10 | 11224005473 |
11 | 483a72748a |
12 | 2212a91655 |
13 | 109b468275 |
14 | 786941009 |
15 | 45a58b3b8 |
hex | 29d00bb61 |
11224005473 has 2 divisors, whose sum is σ = 11224005474. Its totient is φ = 11224005472.
The previous prime is 11224005437. The next prime is 11224005487. The reversal of 11224005473 is 37450042211.
Together with previous prime (11224005437) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8308869409 + 2915136064 = 91153^2 + 53992^2 .
It is a cyclic number.
It is not a de Polignac number, because 11224005473 - 212 = 11224001377 is a prime.
It is not a weakly prime, because it can be changed into another prime (11224005433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612002736 + 5612002737.
It is an arithmetic number, because the mean of its divisors is an integer number (5612002737).
Almost surely, 211224005473 is an apocalyptic number.
It is an amenable number.
11224005473 is a deficient number, since it is larger than the sum of its proper divisors (1).
11224005473 is an equidigital number, since it uses as much as digits as its factorization.
11224005473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 11224005473 its reverse (37450042211), we get a palindrome (48674047684).
The spelling of 11224005473 in words is "eleven billion, two hundred twenty-four million, five thousand, four hundred seventy-three".
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