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11224241341 = 44472524003
BaseRepresentation
bin10100111010000010…
…00101010010111101
31001222020101112112021
422131001011102331
5140441401210331
65053434240141
7545101322455
oct123501052275
931866345467
1011224241341
11483a878715
122212b86051
13109b51b731
147869a2d65
1545a5d6211
hex29d0454bd

11224241341 has 4 divisors (see below), whose sum is σ = 11226769792. Its totient is φ = 11221712892.

The previous prime is 11224241311. The next prime is 11224241389. The reversal of 11224241341 is 14314242211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11224241341 - 211 = 11224239293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11224241311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1257555 + ... + 1266448.

It is an arithmetic number, because the mean of its divisors is an integer number (2806692448).

Almost surely, 211224241341 is an apocalyptic number.

It is an amenable number.

11224241341 is a deficient number, since it is larger than the sum of its proper divisors (2528451).

11224241341 is an equidigital number, since it uses as much as digits as its factorization.

11224241341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2528450.

The product of its digits is 1536, while the sum is 25.

Adding to 11224241341 its reverse (14314242211), we get a palindrome (25538483552).

The spelling of 11224241341 in words is "eleven billion, two hundred twenty-four million, two hundred forty-one thousand, three hundred forty-one".

Divisors: 1 4447 2524003 11224241341